3(t+2)=4+4^5-t(3-147)

Solution for 3(t+2)=4+4^5-t(3-147) equation:

3(t+2)=4+4^5-t(3-147)

We move all terms to the left:

3(t+2)-(4+4^5-t(3-147))=0

We add all the numbers together, and all the variables

3(t+2)-(4+4^5-t(-144))=0

We multiply parentheses

3t-(4+4^5-t(-144))+6=0


We calculate terms in parentheses: -(4+4^5-t(-144)), so:

4+4^5-t(-144)

determiningTheFunctionDomain
-t(-144)+4+4^5

We add all the numbers together, and all the variables

-t(-144)+1028

We multiply parentheses

144t+1028

Back to the equation:

-(144t+1028)


We get rid of parentheses

3t-144t-1028+6=0

We add all the numbers together, and all the variables

-141t-1022=0

We move all terms containing t to the left, all other terms to the right

-141t=1022

t=1022/-141

t=-7+35/141